Comments on "Lorentz contraction, Bell's spaceships and rigid body motion in special relativity"

1、"Lorentz contraction is not what actually occurs for a moving object in special relativity (SR)."

洛伦兹收缩不是狭义相对论中针对运动物体所实际发生的（现象）。

2、"Although there is an equation identical to equation (1) in special relativity, the Lorentz derivation and its application to the Michaelson-Morley experiment contradicts relativity."

尽管在狭义相对论中有一个同（1）式等同的方程（L'=L/γ......（1），其中γ=1/√1-v²，c=1），但是洛伦兹的推导以及他把它应用到MM实验的方式却是有悖于相对论的。

3、"Indeed, if the velocity of light is the same in all directions in any inertial frame, then applying the ‘Lorentz Fitzgerald contraction' to the Michaelson-Morley apparatus would produce a positive result."

的确，如果光在任一惯性系内其速度都是各向相同的，那么把洛伦兹-菲兹杰尔德收缩应用到MM实验将得到一个非零结果。

Bell considered two spaceships starting from rest in a Lorentz system S, and undergoing
identical accelerations a(t) in that system. We analyse this situation now in some detail.

贝尔考虑了在一个洛伦兹系统S中从静止出发的两只飞船，它们相对于该系统做等同的加速运动。我们将详细分析这一场景。

We denote the spaceships as L and R, each having acceleration a(t) in the positive x direction in
system S, starting from rest at positions xL = 0 for the nose of L and xR = d for the tail of
R, so the starting distance between the ships is d.

我们分别以L和R代表两只飞船，每只飞船在S系统内沿着x轴正向的加速度均为a(t)，其中L的鼻部从坐标为xL=0的地方由静止出发，而R的尾部则从坐标为xR=d的地方由静止出发，从而两只飞船的初始距离为d。

At equal times in S with tL = tR = t, the spaceships will have equal velocities v = vL = vR, and the difference xR - xL will remain constant at d.

这样在S系内同一时刻tL=tR=t，两只飞船将拥有相同的速度v=vL=vR，因而其坐标之差xR-xL将保持常数d。

仙人太辛苦了！同时我也太感谢了！！！

原本我只是想让你说说太意的，没想到你直接翻译了！ 

是的，是同一个贝尔；从Jerrold Franklin文中所列参考文献可知。

~无忧仙人

We see that this length is greater than the length between the spaceships before their motion.
That is, as the velocity in S increases, the distance between the spaceships in their rest system
S‘ increases.

我们看到，（4）中的距离d'比两只飞船运动前的距离d要大，也就是说，随着飞船在S系中的速度的增加，飞船在它们所在的静系S’中之间的距离也在增加。

由于加速度均为a(t)，因此不是惯性系，就不能使用匀速关系的洛伦兹变换。

结果，或许该论文将无意义。