有人认为下面爱因斯坦的推导是错的，是不懂数学的结果。请看：x − ct = 0，x' − ct' = 0，而0=λ0，则有(x' − ct') = λ(x − ct)。这不是笑话吗！

有人认为爱因斯坦没有错。

jiuguang的看法呢？

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下面的文字摘自爱因斯坦的《狭义和广义相对论浅说》一书。

A light−signal, which is proceeding along the positive axis of x, is transmitted according to the equation
x = ct
or
x − ct = 0 . . . (1).
Since the same light−signal has to be transmitted relative to K1 with the velocity c, the propagation relative to the system K1 will be represented by the analogous formula
x' − ct' = O . . . (2)
Those space−time points (events) which satisfy (x) must also satisfy (2). Obviously this will be the case when the relation
(x' − ct') = λ(x − ct) . . . (3).
is fulfilled in general, where λ indicates a constant ; for, according to (3), the disappearance of (x −ct) involves the disappearance of (x' − ct').

仍然看不到整个推导过程，也就不明其意。请告诉我这段文字出现在文章的第几章，最好再提供一个网址，或下载的文件。文件可发到下面的E-Mail地址，多谢

liu_zbo@163.com

这一段文字看起来的确有点问题。

如果由于（x-ct)=λ(x'-ct')+b关系成立,当t=t'=0时x=x'=0的确存在关系(x-ct)=λ(x'-ct')。

但不能说由于x-ct=0时x'-ct'=0所以(x-ct)=λ(x'-ct')成立，因为没有事先保证“相对论坐标变换符合线性变换”的前提。